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x^2-10x+7.4=0
a = 1; b = -10; c = +7.4;
Δ = b2-4ac
Δ = -102-4·1·7.4
Δ = 70.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{70.4}}{2*1}=\frac{10-\sqrt{70.4}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{70.4}}{2*1}=\frac{10+\sqrt{70.4}}{2} $
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